Y+ 1 Is a factor of y cube + p write the value of p
Answers
Answered by
6
using remainder theorem
y+1=0
y=-1
p(y)=y^3+p
p(-1)=(-1)^3+p=0
=-1+p=0
=p=1
if my answer is right plz mark as brainliest
y+1=0
y=-1
p(y)=y^3+p
p(-1)=(-1)^3+p=0
=-1+p=0
=p=1
if my answer is right plz mark as brainliest
Answered by
1
Answer:
take y+1=0
then y=0-1
value of y=-1
y^3+p=0
(-1)^3+p=0
-1+p=0
p=0+1
p=1
Similar questions