Question

y = (1+tanx).(1 into sec x) then dy/dx=

Answer 1

Answer:y=(1−tanx)/(1+tanx)dy/dx=sec^x(1-tanx)-(1+tanx)(-sec^x)/(1-tanx) (quotient rule)dy/dx=sec x (1−tanx)−(1+tanx)(−sec x )/(1−tanx)(quotientrule)dy/dx=sec^x-sec^xtanx+sec^x+sec^xtanx/(1-tanx)dy/dx=sec x −sec x tanx+sec x +sec x tanx/(1−tanx)dy/dx=2sec^x/(1-tanx)dy/dx=2sec x /(1−tanx