Question

y = 1/tanx find the dy/dx value​

Answer 1

$\large{ \pink{ \bold{y = \frac{1}{ \tan(x) } }}}$

$\large{ \bold{y = \frac{ \ \cos(x) }{ \ \sin(x) } }}$

${{ \bold{ \frac{dy}{dx} = \frac{ \sin(x) ( - \sin(x) ) - \cos(x) \cos(x) }{ { \sin(x) }^{2} }}}}$

$\large{ { \bold{ \frac{dy}{dx} = \frac{ - { \sin(x) }^{2} - { \cos(x) }^{2} }{ { \sin(x) }^{2} } }}}$

$\large{ { \bold{\frac{dy}{dx} = - 1 - { \cot(x) }^{2} }}}$

$\large{ { \bold{\frac{dy}{dx} = - 1(1 + { \cot(x) }^{2} }}}$

$\large{ \purple{ \bold{ \frac{dy}{dx} = - { \csc(x) }^{2} }}}$

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