y=√1+x/1-x find dy/dx
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Answered by
0
Answer:
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Answered by
6
Answer:
y=
1+x
1−x
y=
(1+x)(1−x)
(1−x)(1−x)
y=
1−x
2
1−x
−(1)
⇒
dx
dy
=
(
1−x
2
)
2
1−x
2
dx
d
(1−x)−(1−x)
dx
d
(
1−x
2
)
⇒
dx
dy
=
1−x
2
−
1−x
2
+(1−x).
1−x
2
x
⇒(1−x
2
)
dx
dy
=
1−x
2
−1+x
2
+x−x
2
⇒(1−x
2
)
dx
dy
=
1−x
2
−1+x
⇒(1−x
2
)
dx
dy
=−(
1−x
2
1−x
)
From (1)
(1−x
2
)
dx
dy
=−y
(1−x
2
)
dx
dy
+y=0
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