Question

y=1/(x^2+2) differentiate by chain rule

Answer 1

$y = \frac{1}{ {x}^{2} + 2 } \\ differentiate \: it \: using \: quotient \: rule \: \\ \\ \frac{dy}{dx} = \frac{ ({x}^{2} + 1) \times \frac{d(1)}{dx} - 1 \times \frac{d( {x}^{2} + 1) }{dx} }{ {(x ^{2} + 1)}^{2} } \\ \\ = > \frac{ - 2x}{ {( {x}^{2} + 1) }^{2} }$
Formula Used :-
$1) \: \: \: \frac{d {x}^{n} }{dx} = n {x}^{n - 1}$

2) d/dx(c) = 0
Where c = any arbitrary constant