Question

Y√1+xsquare dx+x√1+ysquare dy=0

Answer 1

Answer:

Step-by-step explanation:

√(1+x^2).dy+√(1+y^2).dx=0

or. √(1+y^2).dx=-√(1+x^2).dy

or. dx/√(1+x^2) =- dy/√(1+y^2).

Integrating both sides.

log | x+√(x^2+1) | = - log | y+√(y^2+1) | + log | C | . [where C = constant of

integration and not equal to zero ]

log| x+√(x^2+1) | + log | y+√(y^2+1) | = log | C |.

or. {x+√(x^2+1)}.{y+√(y^2+1)}. = C. Answer

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Answer 2

Answer:

Answer:

Step-by-step explanation:

√(1+x^2).dy+√(1+y^2).dx=0

or. √(1+y^2).dx=-√(1+x^2).dy

or. dx/√(1+x^2) =- dy/√(1+y^2).

Integrating both sides.

log | x+√(x^2+1) | = - log | y+√(y^2+1) | + log | C | . [where C = constant of

integration and not equal to zero ]

log| x+√(x^2+1) | + log | y+√(y^2+1) | = log | C |.

or. {x+√(x^2+1)}.{y+√(y^2+1)}. = C. Answer

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