Question

y(1-xy+x²y²)dx+x(x²y²-xy)dy=0​

Answer 1

Answer:

y1-xy( ka square) +x( ka square) y( ka qube) × dx( ka qube) y( la square) - dx( ka square)y + x( ka qube)y( ka square) - x( ka square) y × dy

y1 - dx( ki power 4)y( ki power 4) + dy

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