Question

y-1/y+1=2y-3/2y+3 find the value of y

Answer 1

HEY HERE'S YOUR ANSWER

Y - 1

Y = 1

NOW WE SHOULD ENTER THE VALUE '1' WHEREVER Y IS

Y(1) = 2 × 1 - 3

Y = 2 - 3

Y = -1

Y + 1

Y = 1

NOW WE SHOULD ENTER THE VALUE '-1' WHEREVER Y IS

Y(-1) = 2 × -1 + 3

Y = -2 + 3

Y = 1

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Answer 2

(y-1)(2y+3)=(2y-3)(y+1)

2y^2+3y-2y-3=2y^2+2y-3y-3

2y^2+y=2y^2-y

2y^2+y-2y^2+y=0

2y=0

y=0