Question

(y+1) (y + 4) (y – 5)(y-8) + 50.​

Answer 1

Step-by-step explanation:

(y+1) (y+4) (y-5)(y-8) +50

= [y(y+4) + 1(y+4)] [y(y-8) + 5(y-8)] +50

= [y^2 + 4y + y+4] [y^2-8y + 5y - 40] +50

= [y^2+ 5y +4] [y^2 -3y - 40] +50

= y^2(y^2 -3y - 40) + 5y(y^2 + 5y +4) + 4(y^2+ 5y +4) +50

= y^4 - 3y^3 - 40y^2 + 5y^3+25y^2 +4y +4y^2 +20y +16 +50

=y^4 +2y^3 -11y^2 +24y + 66