Question

y≤-15x +3000 y≤5x In the xy plane, if a point which co-ordinates lies in the solution of the set of inequalities above, what is the maximum possible value for b

Answer 1

Question

y≤-15x +3000 y≤5x In the xy plane, if a point which co-ordinates lies in the solution of the set of inequalities above, what is the maximum possible value for b

$\rule{300}{0.5}$

Answer

The value of b comes out when take equality.  So now we have to solve this equation ⇒ $\sf -15x+3000=5x$ to find the possible value for 'b'.

Let's solve your equation step-by-step.

$\sf -15x+3000=5x$

Step 1: Subtract 5x from both sides.

$\sf -15x+3000-5x=5x-5x$

$\sf -20x+3000=0$

Step 2: Subtract 3000 from both sides.

$\sf -20x+3000-3000=0-3000$

$\sf -20x=-3000$

Step 3: Divide both sides by -20.

$\sf \frac{-20x}{20} = \frac{-3000}{20}$

$\sf x =150$

So now to find the final answer we must multiply 5 from 150.

$\sf 150\times 5 = 750$

∴The maximum possible value of 'b' is 750.

$\rule{300}{0.5}$

Answer 2

Given

• y≤-15x +3000 y≤5x In the xy plane

We Find

• The maximum possible value for b.

According to the question

$Let's \: solve \\ \\ </p><p></p><p> = \sf -15x+3000=5x \\ \\ </p><p></p><p> = \sf -20x+3000=0 \\ \\ </p><p></p><p> = \sf −20x=−3000 \\ \\ </p><p></p><p> = \sf -x= \frac{-3000}{20}\\ \\ </p><p></p><p>\sf x =150 \\ \\ </p><p></p><p>So \: find \: the \: final \: answer \: we \\ \: must \: multiply \: 5 \: from \: 150. \\ \\ </p><p></p><p>\sf = 150\times 5 \\ = 750 \\ \\ \\ </p><p></p><p>∴The \: maximum \: possible \\ value \: of \: 'b' \: is \: 750.</p><p></p><p>$