Physics, asked by adibobade04, 2 months ago

y=1nx/x^2+5x differencation krdoo plz​

Answers

Answered by vishskha29gmailcom
0

Answer:

sorry I didn't know about this que

Answered by s02371joshuaprince47
0

Answer:

y=(5x^2+1)^x

Taking log on both sides,log y=x log(5x^2+1)

Differentiating ,1/y dy/dx=d/dx(x log(5x^2+1))

using product rule, 1/y dy/dx=x.10x/(5x^2+1)+log(5x^2+1)

Now cross multiplying and putting the value of y ,

dy/dx=(5x^2+1)^x(10x^2/(5x^2+1)+log(5x^2+1)).

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