Question

y^2+1/y^2-14 factorizev​

Answer 1

Solution:

x

2

+14x+45

=x

2

+9x+5x+45

=(x

2

+9x)+(5x+45)

=x(x+9)+5(x+9)

=(x+9)(x+5)

Answer 2

Given:

The equation :

${y}^{2} + {1 \div y}^{2} - 14$

To find:

Factorise the equation

Solution:

To factorise the equation you need to first break the equation into two parts.

Breaking the equation as :

${y}^{2} + {1 \div y}^{2} + 2 - 16$

Using the first identify:

${(a + b)}^{2} = {a}^{2} + {b }^{2} + 2ab$

The new equation will look like:

${(y + 1 \div y)}^{2} - 16$

We can also write it as:

${(y + 1 \div y)}^{2} - {4}^{2}$

Using the identity:

${a }^{2} + {b}^{2} = (a + b)(a - b)$

The factorised equation will be:

$(y + 1 \div y + 4)(y + 1 \div y - 4)$