Question

y^2-12+27=0

roots find?

Answer 1

y² - 12y + 27 = 0

y² - 9y - 3y + 27 = 0

y(y - 9) - 3(y - 9) = 0

(y - 9)(y - 3) = 0


So value of y = 3 and 9.


Thank you.

Answer 2

hello mate!....

given.....


$y {}^{2} - 12y + 27 = 0 \\ \\ y {}^{2} - 3y - 9y + 27 = 0 \\ \\ y (y - 3) - 9(y - 3) = 0 \\ \\ (y - 3)(y - 9) = 0 \\ \\ y = 3 \: and \: 9$




HOPE IT HELPS U DEAR.....