Question

Y^2-13y+36=0 then what is the value of y

Answer 1

Answer:

$y = 9 \: and \: 4$

Step-by-step explanation:

$\bf\ {y}^{2} - 13y + 36 = 0 \\ \\ \sf\underline{using \: \: splitting \: \: the \: \: middle \: \: term \: \: method} \\ \\ \tt\ \implies: {y}^{2} - (9y + 4y) + 36 = 0 \\ \\ \tt\ \implies: {y}^{2} - 9y - 4y + 36 = 0 \\ \\ \tt\ \implies: y(y - 9) - 4(y - 9) = 0 \\ \\ \tt\ \implies:(y - 4)(y - 9) = 0 \\ \\ \bf\ y - 9 = 0 \\ \bf\boxed{ \implies:y = 9} \\ \\ \bf\ y - 4 = 0 \\\bf\boxed{ \implies:y = 4 }$

Answer 2

Answer:

$\bf\huge y = 4 \: and \: 9$

Step-by-step explanation:

$\sf\ {y}^{2} - 13y + 36 = 0 \\ \\ \tt\underline{using \: \: splitting \: \: the \: \: middle \: \: term \: \: method} \\ \\ \sf\ \implies: {y}^{2} - (9y + 4y) + 36 = 0 \\ \\ \sf\ \implies: {y}^{2} - 9y - 4y + 36 = 0 \\ \\ \sf\ \implies: y(y - 9) - 4(y - 9) = 0 \\ \\ \sf\ \implies:(y - 4)(y - 9) = 0 \\ \\ \bf\ y - 9 = 0 \\ \sf\boxed{ \implies:y = 9} \\ \\ \bf\ y - 4 = 0 \\\sf\boxed{ \implies:y = 4 }$