Question

(y-2) ² = 5y+3 write in the form of ax²+bx+c=0​

Answer 1

Answer:

y² - 9y + 1 = 0

Step-by-step explanation:

(y-2)² = 5y + 3

(y² + 4 - 4y) - (5y + 3) = 0   .... (a - b)² = a² + b² - 2ab

y² + 4 - 4y - 5y - 3 = 0

y² - 9y + 1 = 0                   .... This is in the Quadratic form (ax²+bx+c=0​), where: a = 1; b= - 9; c = 1; x = y;

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Answer 2

Step-by-step explanation:

$(y - 2) {}^{2} = 5y + 3$

$y {}^{2} - 4y + 4 = 5y + 3$

$y {}^{2} - 4y - 5y + 4 - 3 = 0$

= $y {}^{2} - 9y + 1 = 0$

Value of =

A = 1 , B = -9 , C = 1

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