Math, asked by sakshi3735, 5 months ago

y^2 - 20y + 48 = 0 factorise it​

Answers

Answered by bittukale
1

Answer:

y^2-20y+48=0

y^2-10y-10y+48=0

y(y-10)-2(y-10)=0

(y-2)(y-10)=0

therefore,

y=2 and

y=10

Answered by belwaldeepak123
1

y²-20y+48=0

a=1 ; b=-20 ; c=48

Discriminate=b²-4ac

=(-20)²- 4*1*48

= 400-192

= 208

–––>Next steps are in attachment

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