y^2 - 20y + 48 = 0 factorise it
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Answer:
y^2-20y+48=0
y^2-10y-10y+48=0
y(y-10)-2(y-10)=0
(y-2)(y-10)=0
therefore,
y=2 and
y=10
Answered by
1
y²-20y+48=0
a=1 ; b=-20 ; c=48
Discriminate=b²-4ac
=(-20)²- 4*1*48
= 400-192
= 208
–––>Next steps are in attachment
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