Question

y^2-23y+120=0 solve plz it's urgent ​

Answer 1

Step-by-step explanation:

it's a simple quadratic Equation.

U can check tha above solution.

Answer 2

Answer:

$\boldsymbol {y = 15 \: {\sf or }\: 8}$

Explanation:

Om comapring with the general form of equation ax² + bx + c

We get,

• a = 1
• b = -23
• c = 120

By quadratic formula,

$\boldsymbol{ \implies \: y = \dfrac{ - b\pm \sqrt{ {(b)}^{2} - 4ac} }{2a} }$

Substituting the values,

$\boldsymbol{ \implies \: y = \dfrac{ - ( - 23)\pm \sqrt{ {(23)}^{2} - 4(1)(120)} }{2(1)} }$

On further solving ,

$\boldsymbol{ \implies \: y = \dfrac{ 23\pm \sqrt{ 529 - 480} }{2} }$

$\boldsymbol{ \implies \: y = \dfrac{ 23\pm \sqrt{49} }{2} }$

$\boldsymbol{ \implies \: y = \dfrac{ 23\pm 7 }{2} }$

$\boldsymbol{ \implies \: y = \dfrac{ 23 + 7 }{2} \:{ \sf \ \: or \: } \: \dfrac{23 -7 }{2} }$

$\boldsymbol{ \implies \: y = \dfrac{30}{2} \:{ \sf \ \: or \: } \: \dfrac{16}{2} }$

$\boldsymbol{ \implies \: y = 15{ \sf \ \: or \: } \: 8 }$

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Note:

Quadratic formula,

$\boldsymbol{ \implies \: x = \dfrac{ - b\pm \sqrt{ {(b)}^{2} - 4ac} }{2a} }$

Genral form of a quadratic equation,

$\boldsymbol{ \implies ax^2 + bx + c = 0 }$