Math, asked by amaze23, 4 months ago

-y^2+2xy+3x^2y,when x=1,y=-1

Answers

Answered by rinkum12138

2

Answer:

-6

Step-by-step explanation:

we have,

-y²+2xy+3x²y

x = 1, y = -1

-(-1)²+2(-1)(1)+3(1)²(-1)

= -1-2-3

= -6 ....ans.

Answered by riddhibansal2006

0

Answer:

please mark the brainlest and vote and follow me for more answers

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