(y^2-2y)-2 ^2 solve using identity.Algebra class 8
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Answer:=-3y^4+4
Step-by-step explanation:
(y^2-2y)-2 ^2
As (a-b)^2=a^2+b^2-2ab
And in the question,
(y^2-2y) is "a" and 2 is "b"
So,
[(y^2-2y)-2]^2=(y^2-2y)^2+(2)^2-2[(y^2-2y)-2]
(y^2-2y)^2=(y^2)^2+(2y)^2-2(y^2)(2)
= y^4+4y^2-4y^2
=y^4
So,
[(y^2-2y)-2]^2=(y^2-2y)^2+(2)^2-2[(y^2-2y)(2)]
=y^4+4-2(y^4)(2)
=y^4+4-4y^4
=-3y^4+4
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