(y^2+2y-3)/(y-1)
please
Answers
Answer:
y+3 is the answer.
Step-by-step explanation:
STEP
1
:
y2 + 2y - 3
Simplify ———————————
y - 1
Trying to factor by splitting the middle term
1.1 Factoring y2 + 2y - 3
The first term is, y2 its coefficient is 1 .
The middle term is, +2y its coefficient is 2 .
The last term, "the constant", is -3
Step-1 : Multiply the coefficient of the first term by the constant 1 • -3 = -3
Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is 2 .
-3 + 1 = -2
-1 + 3 = 2 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 3
y2 - 1y + 3y - 3
Step-4 : Add up the first 2 terms, pulling out like factors :
y • (y-1)
Add up the last 2 terms, pulling out common factors :
3 • (y-1)
Step-5 : Add up the four terms of step 4 :
(y+3) • (y-1)
Which is the desired factorization
Canceling Out :
1.2 Cancel out (y-1) which appears on both sides of the fraction line.
Final result :
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