Question

y^2+2y+9=0 factorise
$y {}^{2} + 2y + 9 = 0$
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Answer 1

Step-by-step explanation:

$\textsf{\underline{\pink{Given equation:}}}$

y^2 + 2y + 9 = 0

By comparung the given equation with ax^2 + bx + c = 0, we obtain,

a = 1; b = 2; c = 9

$\textsf{\underline{\purple{By using quadratic formula,}}}$

x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

x = $\frac{-(2) \pm \sqrt{-(2)^2 - 4 \times 1 \times 9}}{2 \times 1}$

x = $\frac{-(2) \pm \sqrt{ 4 - 4 \times 1 \times 9}}{2 \times 1}$

x = $\frac{-(2) \pm \sqrt{4 - 36}}{2}$

x = $\frac{-(2) \pm \sqrt{-24}}{2}$

Since, the value of the discriminator is lesser than zero, no real roots exists.