Question

(y^2+3)^2-16y^2 factorise

Answer 1

Step-by-step explanation:

$\huge\bf\purple{Factorization:-}$

$(y {}^{2} + 3) {}^{2} - 16y {}^{2} \\ = (y {}^{2} + 3) {}^{2} - (4y) {}^{2} \\ = (y {}^{2} + 4y + 3)(y {}^{2} - 4y + 3)$

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Answer 2

$\huge\mathbb\green{Solution}$

${({y}^{2} + 3)}^{2} - 16{y}^{2} \\ \\ using formula \\ \\ \boxed{\boxed{\boxed{ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} }}} \\ \\ {y}^{4} + 2 × {y}^{2} × 3 + {3}^{2} - 16{y}^{2} \\ \\ {y}^{4} + 6{y}^{2} + 9 - 16{y}^{2} \\ \\ {y}^{4} - 10{y}^{2} + 9$