Question

y^2-32y-105... solve this​

Answer 1

Answer:

1.1 Factoring y2-32y+256

The first term is, y2 its coefficient is 1 .

The middle term is, -32y its coefficient is -32 .

The last term, "the constant", is +256

Step-1 : Multiply the coefficient of the first term by the constant 1 • 256 = 256

Step-2 : Find two factors of 256 whose sum equals the coefficient of the middle term, which is -32 .

-256 + -1 = -257

-128 + -2 = -130

-64 + -4 = -68

-32 + -8 = -40

-16 + -16 = -32 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -16 and -16

y2 - 16y - 16y - 256

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-16)

Add up the last 2 terms, pulling out common factors :

16 • (y-16)

Step-5 : Add up the four terms of step 4 :

(y-16) • (y-16)

Which is the desired factorization

Multiplying Exponential Expressions:

1.2 Multiply (y-16) by (y-16)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (y-16) and the exponents are :

1 , as (y-16) is the same number as (y-16)1

and 1 , as (y-16) is the same number as (y-16)1

The product is therefore, (y-16)(1+1) = (y-16)2

Final result :

(y - 16)2

Step-by-step explanation:

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Answer 2

Y^2-32Y-105

By using (a-b)^2 = a^2 -2ab +b^2....... (00)

HERE ,a=Y;

Therefore,

Y^2-32Y-105...... 1

=> (Y)^2- 2 (Y)(- root105)+(-root105)^2

=> (Y-105)^2

By using Eq. (00)

Solved..

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