y
2
4
(i) x+
(1)
*+2y = 5
3
dir 0.5
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4
Answer:
❇️⭕Here is your answer mate ⭕❇️
The given system of equation is
x/(y/2) =4...(i)
(x/3)+2y =5...(ii)
From (1) we get
(2x+y)/2 =4
2x+y=8
y=8-2x
From (2) we get,
x+6y=15..(iii)
Substituting y=8-2x in (iii), we get
x+6(8-2x)=15
x+48-12x=15
=> - 11x =15-48
=> - 11x= -33
=> x= (- 33/-11) =3
Putting x= 3 in y=8-2x we get,
y= 8-2*3
y=8-6
y=2
Hence the solution of the given system is x=3, y=2
Hope it helps u..☺️☺️✌️✌️
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