Question

y^2-4y+3 factorise
the given polynomial as quadratic polynomial

Answer 1

Answer:

You can solve it by middle term splitting or by quadratic formula.

the equation is

$y ^{2} - 4y + 3$

now the factors will be (y-3)(y-1)

Step-by-step explanation:

multiply the polynomial with degree 2 with the constant and think of the two numbers that when multiplied yields the middle term.

Hope you understand

Answer 2

Answer:

y²-4y+3

y²-(3+1)y+3

y²-3y-y+3

y(y-3)-1(y-3)

(y-3) (y-1)

hope it will help you