Math, asked by rashmirajeshtiwari, 1 month ago

(y-2/5x)^3
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Answered by Anonymous
21

 \small \bold{( \frac{y - 2}{5x} ) {}^{3}  = ( \frac{y}{5x}  -  \frac{2}{5x} ) {}^{3}   \: using \: (a - b) {}^{3}}

 \bold{ \rightarrow \:  {a}^{3}  -  {b}^{3}  -  3ab \: (a - b)}

 \small \bold{ \implies \: ( \frac{y}{5x} ) {}^{3}  - ( \frac{2}{5x} ) {}^{3}  - 3(  \frac{y}{5x}  )( \frac{2}{5x} )[ \frac{y}{5x}  -  \frac{2}{5x} ]}

 \bold{ \implies \:  \frac{ {y}^{3} }{125 {x}^{3} }  -  \frac{8}{125x}  -  \frac{6y}{25 {x}^{2} } ( \frac{y - 2}{5x} )}

Answered by studylover001
113

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