y^2 - 5y - 24 factorize the following polynomials (step by step)
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Put (y2 + 5y) = a
⟹ a (a -2) – 24
⟹ a2 -2a – 24
⟹ a2 -6a + 4a – 24
⟹ a (a – 6) + 4 (a – 6)
⟹ (a + 4) (a – 6)
⟹ But a = (y2 + 5y)
⟹ ((y2 + 5y) + 4) ((y2 + 5y) – 6)
⟹ (y2 + 5y + 4) (y2 + 5y – 6)
⟹ (y2 + 4y + y + 4) (y2 + 6y - y – 6)
⟹ (y (y + 4) + 1 (y + 4)) (y (y + 6) – 1 (y + 6))
⟹ (y + 4) (y + 1) (y + 6) (y – 1)
Therefore, the factorized form = (y + 4) (y + 1) (y + 6) (y – 1)
Put (y2 + 5y) = a
⟹ a (a -2) – 24
⟹ a2 -2a – 24
⟹ a2 -6a + 4a – 24
⟹ a (a – 6) + 4 (a – 6)
⟹ (a + 4) (a – 6)
⟹ But a = (y2 + 5y)
⟹ ((y2 + 5y) + 4) ((y2 + 5y) – 6)
⟹ (y2 + 5y + 4) (y2 + 5y – 6)
⟹ (y2 + 4y + y + 4) (y2 + 6y - y – 6)
⟹ (y (y + 4) + 1 (y + 4)) (y (y + 6) – 1 (y + 6))
⟹ (y + 4) (y + 1) (y + 6) (y – 1)
Therefore, the factorized form = (y + 4) (y + 1) (y + 6) (y – 1)
Answered by
1
Answer:
y^2-5y-24
y^2-8y+3y-24
y(y-8)+3(y-8)
(y-8)(y+3)
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