(y+2)/6 - 1/(y+2) = 1/6. So what do s the solution set of this question
Answers
Answer:
1) x/7 + y/3 = 5 x/2 - y/9 = 6
On taking LCM of denominators and simplifying, we get the linear equations as
3x + 7y = 105 → (1)
9x − 2y = 108 → (2)
Multiply equation(1) with 3 , we get
9x + 21y = 315 → (3)
Now subtract (2) from (3)
9x + 21y = 315
9x − 2y = 108
----------------------
23y = 207
∴ y = (207/23) = 9
Put y = 9 in 3x + 7y = 105
3x + 7(9) = 105
⇒ 3x = 105 − 63 = 42
∴ x = (42/3) = 14
2) 4x + 6/y = 15
3x - 4/y = 7
put (1/y) = p
Hence the above equations become,
4x + 6p =15 → (1)
3x − 4p = 7 → (2)
Multiply equation (1) with 4 and equation (2) with 6 and add as shown
16x + 24p = 60
18x − 24p = 42
----------------------
34x = 102
∴ x = (102/34) = 3
Put x = 3 in 4x + 6p =15
4(3) + 6p = 15
12 + 6p = 15
6p = 3
∴ p = (3/6) = (1/2)
⇒ (1/y) = (1/2)
∴ y = 2
Solve the following system of linear equations by elimination-method
2/x + 2/3y = 1/6 , 3/x + 2/y = 0
Solution:
2/x + 2/3y = 1/6 ---- (1)
3/x + 2/y = 0 ---- (2)
Let 1/x = a and 1/y = b
2 a + (2b/3) = 1/6
(6 a + 2 b)/3 = 1/6
6 (6 a + 2 b ) = 3
36 a + 12 b = 3
Dividing the whole equation by 3 we get
12 a + 4 b = 1 ------- (1)
3 a + 2 b = 0 ---------(2)
12 a + 4 b = 1
There are two unknowns in the given equations. By solving these equations we have to find the values of a and b. For that let us consider the coefficients of a and b in both equation. In the first equation we have + 4b and in the second equation also we have + 2b and the symbols are same so we have to subtract them for eliminating the variable b.
Multiply the second equation by 2 => 6 a + 4 b = 0
Subtracting the second equation from the first equation
12 a + 4 b = 1
6 a + 4 b = 0
(-) (-) (-)
--------------
6 a = 1
a = 1/6
now we have to apply the value of a in either given equations to get the value of another variable b
Substitute a = 1/6 in the first equation we get
12(1/6) + 4 b = 1
2 + 4 b = 1
4 b = 1- 2
4 b = -1
b = -1/4
Solution:
x = 6
y = -4
verification:
2/x + 2/3y = 1/6
2/6 + 2/3(-4) = 1/6
1/3 -1/6 = 1/6
1/6 = 1/6
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