Y = 2, but how???
Please help me guys with process..
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Answers
Answered by
1
Answer:
(y+7)/5 = 1 + (3y-2)/5
y+7 = 5+3y-2
2y = 4
y= 2
hope the answer helps
Answered by
0
Answer:
Solve
1
Multiply the numbers
+
7
5
=
1
+
3
−
1
⋅
2
5
y+\frac{7}{5}=1+3y{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{2}{5}}}
y+57=1+3y−1⋅52
+
7
5
=
1
+
3
−
2
5
y+\frac{7}{5}=1+3y{\color{#c92786}{-\frac{2}{5}}}
y+57=1+3y−52
2
Subtract the numbers
+
7
5
=
1
+
3
−
2
5
y+\frac{7}{5}={\color{#c92786}{1}}+3y{\color{#c92786}{-\frac{2}{5}}}
y+57=1+3y−52
+
7
5
=
3
5
+
3
y+\frac{7}{5}={\color{#c92786}{\frac{3}{5}}}+3y
y+57=53+3y
3
Rearrange terms
+
7
5
=
3
5
+
3
y+\frac{7}{5}={\color{#c92786}{\frac{3}{5}+3y}}
y+57=53+3y
+
7
5
=
3
+
3
5
Step-by-step explanation:
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