y = 2 (cm) sin [πt/2 + ∅] what is the maximum acceleration of
the particle doing the S.H.M.
(a) π/2 cm/s²
(b) π²/2 cm/s²
(c) π²/4 cm/s²
(d) π/4 cm/s²
Answers
Answered by
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Answer:
=2sin[
2
πt
+ϕ], where 2 is in cm
Compare the equation with the standard equation,
A=sin(wt+ϕ)
⇒A=2 cm,w=
2
π
Acceleration of the particle is
a=w
2
x
At x=+A,a=a
max
∴a
max
=w
2
A=
2
π
2
cm/s
2
Explanation:
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