Question

y = 2 (cm) sin [πt/2 + ∅] what is the maximum acceleration of
the particle doing the S.H.M.
(a) π/2 cm/s²
(b) π²/2 cm/s²
(c) π²/4 cm/s²
(d) π/4 cm/s²

Answer 1

Answer:

=2sin[

2

πt

+ϕ], where 2 is in cm

Compare the equation with the standard equation,

A=sin(wt+ϕ)

⇒A=2 cm,w=

2

π

Acceleration of the particle is

a=w

2

x

At x=+A,a=a

max

∴a

max

=w

2

A=

2

π

2

cm/s

2

Explanation:

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