Math, asked by thakarechinmay, 1 year ago

 y^{2} + k^{2} = 2y (k+1)

Find value of k   

Answers

Answered by lipi
1
Y^2+K^2=2KY+2Y
S0
Y^2-2KY+K^2=2Y
(Y-K)^2=2Y
Y-K=SQRT OF 2Y
SO K=Y-SQRT OF 2Y

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