Math, asked by malooottyy, 9 months ago

Y= 2/sin thetta + root 3 cos thetta, diffrentiate it

Answers

Answered by dnavneetk9549
1

Answer:hi here is ur answer !!!

Step-by-step explanation:

The given equation is:

y=\frac{2}{sin{\theta}}+\sqrt{3}cos{\theta}

y=2cosec{\theta}+\sqrt{3}cos{\theta}

Differentiating the above equation with respect to {\theta}, we get

\frac{dy}{d{\theta}}=2(-cosec{\theta}cot{\theta})+\sqrt{3}(-sin{\theta})

\frac{dy}{d{\theta}}=-2cosec{\theta}cot{\theta}-\sqrt{3}sin{\theta}

\frac{dy}{d{\theta}}=-(cosec{\theta}cot{\theta}+\sqrt{3}sin{\theta})

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