Y= 2/sin thetta + root 3 cos thetta, diffrentiate it
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Answer:hi here is ur answer !!!
Step-by-step explanation:
The given equation is:
y=\frac{2}{sin{\theta}}+\sqrt{3}cos{\theta}
y=2cosec{\theta}+\sqrt{3}cos{\theta}
Differentiating the above equation with respect to {\theta}, we get
\frac{dy}{d{\theta}}=2(-cosec{\theta}cot{\theta})+\sqrt{3}(-sin{\theta})
\frac{dy}{d{\theta}}=-2cosec{\theta}cot{\theta}-\sqrt{3}sin{\theta}
\frac{dy}{d{\theta}}=-(cosec{\theta}cot{\theta}+\sqrt{3}sin{\theta})
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