(y-2)(y+1)=0 solve quadratic equation
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2
HELLO!!!!
(y-2)(y+1)=0
y^2+1y-2y-2 = 0.
y^2 -y -2 = 0
y^2- 2y +y -2 =0
y(y-2)+1(y-2) =0
(y-2) (y+1) =0
So,y = 2 & y = -1
THANKS
HOPE IT HELPS U☆☆☆
(y-2)(y+1)=0
y^2+1y-2y-2 = 0.
y^2 -y -2 = 0
y^2- 2y +y -2 =0
y(y-2)+1(y-2) =0
(y-2) (y+1) =0
So,y = 2 & y = -1
THANKS
HOPE IT HELPS U☆☆☆
Answered by
3
y-2=0 & y+1=0. y =2 & y= -1
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