Question

Y^2 +y/2-3 =0 ,than find the value of y.
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Answer 1

${y}^{2} + \frac{y}{2} - 3 = 0 \\ 2 {y}^{2} + y - 3 = 0 \\ 2 {y}^{2} - 2y + 3y - 3 = 0 \\ 2y(y - 1) + 3(y - 1) = 0 \\ (y - 1)(2y + 3) = 0$

So, Value of y are 1 or -3/2

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Answer 2

Answer:

-2 and 3/2

step to step explanation:

y^2 + y/2-3 =0

2y^2 + y - 6 =0

2y^2 +4y -3y - 6 = 0

2y ( y + 2 ) - 3 ( y + 2) = 0

(y + 2) ( 2y - 3) = 0

so,

y = -2

y = 3 /2

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