Math, asked by krishansharma94, 7 months ago

(y+2)(y-3)=(y-6)(y+9)+8​

Answers

Answered by mail2ranvir05
6

Answer:

y = 10

Step-by-step explanation:

(y+2)(y-3) = (y-6)(y+9) + 8:

y(y-3) +2(y-3) = y(y+9) -6(y+9) + 8

y² - 3y +2y -6 = y² + 9y - 6y -54 + 8

y² - y - 6 = y² + 3y - 46

y² - y - 6 - y² - 3y + 46 = 0

- 4y + 40 = 0

- 4y = - 40

Therefore y = 10

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