Math, asked by khanweldingjalp7c8ah, 1 year ago

(y+2)(y_3)(y+8)(y+3)+56

Answers

Answered by hussain036
1
(y-3)(y+3)(y+2)(y+8) + 56
= (y^2 - 3^2){(y(y+8)+2(y+8)} + 56.
= (y^2 - 9){y^2 + 8y + 2y + 16} + 56
= (y^2 - 9){y^2 + 10y + 16} + 56
= {(y^2(y^2 + 10y + 16} -9(y^2 + 10y + 16)} +56
y^4 + 10y^3 + 16y^2 - 9y^2 - 90y - 144 + 56
y^4 + 10y^3 + 7y^2 - 90y - 88
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