Question

(y+2)(y+3)(y-8)(y+3)+56 factotisation​

Answer 1

Answer:

(y+2)(y+3)(y-8)(y+3)+56

=

${y}^{3} {3y}^{2} - 34y + 8$

Step-by-step explanation:

$(y + 2)(y + 3)(y - 8) + 56 \\ = ( {y}^{2} + 3y + 2y + 6)(y - 8) + 56 \\ = {y}^{3} - 8 {y}^{2} + 3 {y}^{2} - 24y + 2 {y}^{2} - 16y + 6y - 48 + 56 \\ = {y}^{3} - 8 {y}^{2} + {3y}^{2} + {2y}^{2} - 24y - 10y + 8 \\ = {y}^{3 } { - 3y}^{2} - 34y + 8$