Question

y^2(y-px)=x^4p^2 where p =dy/dx​

Answer 1

Answer:

The given differential equation is y + px = x4p2 ...(i) Differentiating w.r.t. x, we get Integrating, we get log p + 2log x = log c px2 = c ...(ii) Eliminating p between Eqs (i) and (iii), we get the required solution of Eq. (i) y + (c/x) + c2 which is the required solutionRead more on Sarthaks.com - https://www.sarthaks.com/563970/y-px-x-4p-2