Chemistry, asked by lazzylavender, 1 month ago

Y + 2HCI ZnCl2 + H2. In the above reaction, Y is: (a) Aluminium (b) Copper (c) Sodium (d) Zinc​

Answers

Answered by jagtapraghav9
12

Answer:

zinc

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Answered by Rameshjangid
1

Final answer: (d) Zinc

Given that: We are given Y + 2HCI → ZnCl₂ + H₂

To find: We have to find Y.

Explanation:

  • Given reaction is Y + 2HCI → ZnCl₂ + H₂

Which is a type of displacement reaction. The term displacement reaction means the element present in the solution is displaced by another element which is reacted to it.

  • Here displacement product as a result of displacement reaction is ZnCl₂ and the reactant solution is HCl which means Zinc Zn displacing Hydrogen H from HCl solution to form ZnCl₂. So Y = zinc Zn. The complete reaction is,

               Zn + 2HCl → ZnCl₂ + H₂

So option (d) Zinc is correct answer.

  • Al+ 6HCl → AlCl₃ + 3H₂

Here 6 moles of HCl is required to get AlCl₃, but given reaction contain 2 moles of HCl also the product formed is AlCl₃ which is not the desired one so option (a) Aluminium is wrong.

  • According to reactivity series the reactivity of copper is less than that of hydrogen. By that way copper doesnot displace hydrogen in HCl to form CuCl₂. So there will be no reaction. Hence option (b) copper is wrong.
  • 2Na + 2HCl → 2NaCl +H₂

which is a single displacement reaction. The product formed is NaCl which is not given product. So (c) Sodium also wrong.

To know more about the concept please go through the links

https://brainly.in/question/23575349

https://brainly.in/question/9120741

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