y=[2x-1]=3[x-6], find 3[x+y]
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3[x+y]
y = 2x -1 ,= 3(x -6)
y = 2x -3x -1 +9
y = -x +8
then we find ....
3 [ x+ y]
3 [ x + (-x +8)]
3 [ x- x + 8 ]
3 [ 0 + 8 ]
3×0 + 3×8
0+ 24
24 .......
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