Question

y=[2x-1]=3[x-6], find 3[x+y]​

Answer 1

3[x+y]

y = 2x -1 ,= 3(x -6)

y = 2x -3x -1 +9

y = -x +8

then we find ....

3 [ x+ y]

3 [ x + (-x +8)]

3 [ x- x + 8 ]

3 [ 0 + 8 ]

3×0 + 3×8

0+ 24

24 .......