Math, asked by sujal1994, 10 months ago

Y=(2X+1)^5 differentiate

Answers

Answered by BendingReality
9

Answer:

\displaystyle \sf \longrightarrow 10.\left( 2 x+1 \right)^{4} \\

Step-by-step explanation:

Given :

\displaystyle \sf y = \left( 2 x+1 \right)^5 \\ \\

We are asked to find y' :

Diff. w.r.t x :

Applying power rule and chain rule here we get :

\displaystyle \sf \longrightarrow y' = 5\left( 2 x+1 \right)^{5-1}.\left( 2 x+1 \right)' \\ \\

\displaystyle \sf \longrightarrow y' = 5\left( 2 x+1 \right)^{4}.\left( 2 x+1 \right)' \\ \\

\displaystyle \sf \longrightarrow y' = 5\left( 2 x+1 \right)^{4}.\left( 2+0 \right) \\ \\

\displaystyle \sf \longrightarrow y' = 5\left( 2 x+1 \right)^{4}.\left( 2 \right) \\ \\

\displaystyle \sf \longrightarrow y' = 10.\left( 2 x+1 \right)^{4} \\ \\

Hence we get required answer!

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