Question

Y+ 2X-19=0; 2x-3y + 3 =0​

Answer 1

Answer:

• $x = \frac{27}{4}$
• $y =\frac{11}{2}$

Given pair of linear equations:

y + 2x-19 =0

= 2x + y -19 =0 ------------------------( 1 )

&

 2x - 3y + 3 = 0 ----------------------( 2 )

To solve:

The pair of linear equations and hence find the value of x and y respectively.

Proof:

Subtracting equation ( 1 ) from  equation ( 2 ), we get:

= 2x - 3y + 3 - ( 2x + y - 19) = 0 -0

⇒ 2x - 3y + 3 -2x - y + 19 = 0

⇒ 2x -2x - 3y -y + 3 + 19 = 0

⇒ -4y + 22 = 0

⇒ -4y = -22

⇒ y = $\frac{-22}{-4}$

⇒ $y =\frac{11}{2}$

Substituting the value of y in equation ( 1 ), we get:

= 2x + y - 19 = 0

⇒ $2x +\frac{11}{2} - 19 = 0$

⇒ $2x + \frac{11- 38 }{2} = 0$

⇒ $2x + (\frac{-27}{2} )= 0$

⇒ $2x = \frac{27}{2}$

⇒ $x = \frac{27}{2 X 2}$

⇒ $x = \frac{27}{4}$

Hence, Proved.

Hope you got that.

Thank You.