Math, asked by radhikaravi3793, 5 months ago

y-2x-3.......-(1)
4x-5y-2......-(2)
substitution method solution 10 th std pair of linear equation in two variables lessons plz solve it​

Answers

Answered by nikitamaurya2004rm
0

Step-by-step explanation:

y=2x+3...... (1)

4x-5(2x+3) -2

4x-10x-15-2

-6x-17

x=17/-6

x=-17/6

putting the value of x in equation 1

y-2x-3

y-2(-17/6) -3

y=2(-17/6) +3

y=-34/6+3

y=-34+18/6

y=-16/6

y=-8/3

x=-17/6 , y=-8/3

Answered by dami897
1

Answer:

y=2x+3...... (1)

4x-5(2x+3) -2

4x-10x-15-2

-6x-17

x=17/-6

x=-17/6

putting the value of x in equation 1

y-2x-3

y-2(-17/6) -3

y=2(-17/6) +3

y=-34/6+3

y=-34+18/6

y=-16/6

y=-8/3

x=-17/6 , y=-8/3

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