y= 2x dy/dx + y² (dy/dx)³
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Answer:
Correct options are B) and C)
Given, (x+y)(dx−dy)=dx+dy.
(x+y+1)dy=(x+y−1)dx
dx
dy
=
x+y+1
x+y−1
.
⇒
x+y
dx+dy
=dx−dy.
Integrating we get,
log(x+y)=x−y+c
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