Physics, asked by yashchhabra1000, 9 months ago


y = 2x² - kx + 5. find the value of k if = dy/dx=8 at x = 2
Options
1. 16
2. 8
3. 4
4. 0
place answer fast ​

Answers

Answered by Anonymous
23

Answer:

differentiating we get

Explanation:

4x - k

since dy/dx = 8

4x - k = 8

4(2) - k = 8

k = 0

Answered by Anonymous
85

GiveN :

  • y = 2x² - kx + 5
  • dy/dx = 8 at x = 2

To FinD :

  • Value of k

SolutioN :

Take Given equation :

\longrightarrow \sf{y \: = \: 2x^2 \: - \: kx \: + \: 5} \\ \\ {\small{\sf{ \: \: \: \: \: \: \: \: Differentiate \:  wrt. \:  x}}} \\ \\ \longrightarrow \sf{\dfrac{dy}{dx} \: = \: \dfrac{d(2x^2 \: - \: kx \: + \: 4)}{dx}} \\ \\ \longrightarrow \sf{\dfrac{dy}{dx} \: = \: 2(2x) \: - \: k \: + \: 0} \\ \\ \longrightarrow \sf{\dfrac{dy}{dx} \: = \: 4x \: - \: k}

Now, put value of dy/dx and at x = 2

So,

\longrightarrow \sf{8 \: = \: 4x \: - \: k} \\ \\ \longrightarrow \sf{8 \: = \: 4(2) \: - \: k} \\ \\ \longrightarrow \sf{8 \: = \: 8 \: - \: k} \\ \\ \longrightarrow \sf{-k \: = \: 8 \: - \: 8} \\ \\ \longrightarrow \sf{-k \: = \: 0} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \:  \Large{\underline{\boxed{\sf{k \: = \: 0}}}}

Similar questions