Question

y (2xy + 1) dx - xdy = 0 solve the differential equation ​

Answer 1

Step-by-step explanation:

y(2xy+1)dx - xdy = 0

y(y^3-x)dx + x(y^3+x)dy = 0

(x^3+y^3+1)dx + x^4y^2dy = 0

2tds +s(2+s^2t)dt = 0

y(x^4-y^2)dx + x(x^4+y^2)dy = 0

Expert's answer

mark as brainlist