Question

Y(2y+3) – 2y (7-5) = 26
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Answer 1

Answer:

$y (2y + 3) - 2y(7 - 5) = 26$

$2 {y}^{2} + 3y - 14y + 10y = 26$

$2 {y}^{2} - y = 26$

$2 {y}^{2} - y - 26 = 0$

This can further solved by factorization method...

Answer 2

Step-by-step explanation:

y*(2y+3)-2y(7-5)=26

y*2y=2y

y*3=3y

2y+3y-2y(2)=26

2y+3y-2y*2=26

2y+3y-2y=26/2

26/2=12

2y+3y-2y=12

2y+3y=5y

5y-2y=12

5y-2y=3y

3y=12

y=12/3

y=4