Math, asked by uditanand49, 9 months ago

y^3-1/64x^3 factorise​

Answers

Answered by dewanganajay1875
3

Answer:

Formula: a^3- b^3= (a-b)(a^2-ab+b^2)

=(y)^3- (4x)^3

=(y-4x)(y^2-4xy+y^2)

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Answered by ahanatarafder06
4

Answer:

 {a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2}  + ab +  {b}^{2} )

 {y}^{3}  -   \frac{1}{64 {x}^{3} }

 =  {y}^{3}  -   {(\frac{1}{4x}) }^{3}

 = (y -  \frac{1}{4x} )( {y}^{2} + (y)( \frac{1}{4x}  ) +  \frac{1}{ {4x}^{2} } )

 = (y -  \frac{1}{4x} )( {y}^{2}  +  \frac{y}{4x}  +  \frac{1}{16 {x}^{2} } )

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