y-3=2(x+1)y−3=2(x+1) find the missing value
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y-3=2(X+1)
or,y-3=2x+2
or,2x-y=-1......(1)
y-3=2(X+1)y
or,y-3=2x+2y
or,2x+y=-3.....(2)
solving both equation
2x-y=-1
-2x+y=-3
.............................
4x=-4
X=-1
putting the value of X in equation 1
-2-y=-1
or,-y=-1+2
=1
or,y=-1
which is the missing values ...
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