Question

y^3 - 2 y square - 29 Y - 42​

Answer 1

Answer:

(y+2)(y+3)(y-7)

Step-by-step explanation:

${y}^{3} - 2y ^{2} - 29y - 42 = 0 \\ putting \: y = - 2 \\ - 8 - 8 + 58 - 42 = 0 \\ so \: f(x) = (y + 2)( {y}^{2} - 4y - 21) \\ = (y + 2)(y + 3)(y - 7)$

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